CSAT 2nd Second Paper 4 solution

 1. Age of left = previous age - name of  person present * increase in average age 

                 =15-(10-1)*(18-15)

                =15-9*1

                =15-9= 6 years


2. ( 5 +1)(2 *5+1) / 6 = 6*11/6=66/6=11


3)  (10 +1) (10+2)/3

=11*12/3= 132/3

=44

4)  n+1/2            =          9+1/2=10/2 =5



5) average speed = 2xy/x+y

=2*15*12 all divided by15 +12

= 360/27= 131/3


6)  20= 200000

    12*12500=150000

remains8(200000-150000)

=50000

= 50000/8 =  6250


7)10*26=260

lets tax passed and failed student is x 

Average failed student = (10 -x) 

passed = 80*x= 80x

failed student (10 - x  )* 20 

= 200 - 20 x

80x +200 - 20x = 260

60 x = 60

x = 60/60 = 1

8. E D C A B

9.b


11.5% increase = 16000 *5/100= 800

16000+800=16800 salary

reduce transport allowance = 800

16800 - 800 = 16000.

12. lets tax passed and failed student is =x 

average failed = (10-x)

passed = 80 * x = 80x 

failed = (10-x)*20

200-20x

80x+200-20x= 260

60x = 260 -200

60x=60

x=60/60=1


14. Dice = ( 1,2,3,4,5,6)

n(s) = 6( 1,2,3,4,5,6)

n(E) = 3( 2, 4, 6)=3/6=1/2


15) Multiple of 2 = 3 , 6

n(E) = 2( 3,6)

n(s) = 6( 1,2,3,4,5,6)



 



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